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Bug #2706 » py_request.py

Alexey Vishnyakov, 11/23/2018 10:24 AM

 
import requests

s = requests.Session()
s.get('http://192.168.56.3/index.html')
s.get('http://192.168.56.3/index.html?xss=<img src=x onerror=alert(0)>')
(2-2/7)